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18 votes
How much wrapping paper would you need to cover a rectangular

box that is 19 inches by 12 inches by 3 inches if you need 10% more
wrapping paper than the surface area of the box? Give your answer
to the nearest square inch.

PLEASE HELP T-T

User Aternus
by
2.7k points

1 Answer

7 votes

Explanation:

a box (like a "deformed" die) has 6 sides.

and in case of such a rectangular box there are 3 pairs of equal sides.

the area of each side is a rectangle.

top and bottom : 19×12 times 2

front and back : 19×3 times 2

left and right : 12×3 times 2

so, we get

19×12×2 + 19×3×2 + 12×3×2 = 642 in²

and now, we need 10% more.

10% = 642/10 = 64.2 in²

the total is then

642 + 64.2 = 706.2 ≈ 706 in²

User Mariano Peterson
by
3.3k points