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Having trouble with this and 3 other problems

Having trouble with this and 3 other problems-example-1
User Entela
by
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1 Answer

4 votes

Answer:

a.) 10

b.) -2

c.) 6

d.) y = 6

e.) T = π

f.) y = -6cos(2t) + 4

Explanation:

a.) Max value is the highest value in the y-axis. It peaks at y=10

b.) Min value is the lowest value in the y-axis. Peaks at y=-2

c.) Amplitude is how high the peak is from the midpoint. It could be found by taking the average of the peaks. (10 - (-2))/2 = 6

d.) y = 6

e.) T = π

f.) General equation for a sinusoidal wave is

y = Acos(ωt - Ф) + k

y = Acos((2π/T)t - Ф) + k

The graph started at it's min, so the amplitude must had been fliped upsidedown because it normally starts at the max. Therefore I must make my equation negative to flip it.

y = -Acos((2π/T)t - Ф) + k

  • A = amplitude = 6
  • T = period = π
  • Ф = phaseshift = 0
  • k = shift_in_y_direction = 4 , because shifting from -6 to -2 is shifting 4 units up

y = -(6)cos((2π/(π))t - (0)) + (4)

y = -6cos(2t) + 4

User KurtMica
by
3.3k points