Question

2. A 0.30 kg ball is dropped onto a concrete driveway. The ball's velocity before impact is 4.5 m/s and after impact is 4.2 m/s. What is the change in the ball's momentum?

Answer 1

-0.09 kgm/s

Step-by-step explanation:

Change in momentum: This can be defined as the product of mass a body and it's change in momentum. The S.I unit of change in momentum is kgm/s.

The formula of change in momentum is

ΔM = m(v-u)......................... Equation 1

Where ΔM = change in momentum of the ball, m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball.

Given: m = 0.30 kg, u = 4.5 m/s, v = 4.2 m/s

Substitute into equation 1

ΔM = 0.3(4.2-4.5)

ΔM = 0.3(-0.3)

ΔM = -0.09 kgm/s

Hence the change in momentum of the body = -0.09 kgm/s