Question

A total of 620 C of charge passes through a flashlight in 0.510 h. What is the average current in milliamperes?

Answer 1

Step-by-step explanation:

The given data is as follows.

Q = 620 C, t = 0.510 hour

First, we will convert hours into seconds. Since, there are 3600 seconds present in 1 hour. Hence, number of seconds present in 0.510 hour are as follows.

`0.510 hr * (3600 sec)/(1 hr)`

= 1836 sec

Therefore, we will calculate the average current as follows.

I =
`(Q)/(t)`

=
`(620 C)/(1836 sec)`

= 0.337 C/sec

It is known that,

1 C/sec = 1000 mA

So,
`0.337 C/sec * (1000 mA)/(1 C/s)`

= 337 mA

Thus, we can conclude that the average current in milliamperes is 337 mA.