Answer:
The curve should be banked at 13.1°
Explanation:
The free body diagram for the car on the road is shown in the image attached to this solution.
ΣFₓ = 0, ΣFᵧ = 0,
The forces in the x-direction include the Nₓ (x-component of the Normal Reaction of the road on the car) and the (mv²/r) force keeping it in circular motion.
Nₓ = N sin θ and mv²/r
The forces in the y-direction include the Nᵧ (y-component of the normal reaction of the road on the car) and the weight of the car, mg
Nᵧ = N cos θ and mg
Putting the equations together,
N sin θ = mv²/r (eqn 1)
N cos θ = mg (eqn 2)
Divide (eqn 1) by (eqn 2)
(N sin θ)/(N cos θ) = (mv²/r)/(mg)
tan θ = v²/gr
v = 25 m/s
r = 274 m
Tan θ = 25²/(9.8 × 274) = 0.2328
θ = Tan⁻¹ (0.2328) = 13.1°