Question

Sodium metal is sometimes used as a cooling agent in heat exchange units because of its relatively high molar heat capacity of 28.2 J/mol°C. What is the specific heat of sodium in J/g°C?

Answer 1

The specific heat of sodium is calculated by dividing the molar heat capacity of 28.2 J/mol°C by its molar mass of 23.0 g/mol, resulting in 1.226 J/g°C. Sodium's relatively high specific heat compared to other metals makes it useful as a cooling agent in heat exchange units.

Step-by-step explanation:

The specific heat capacity of sodium in J/g°C can be calculated by taking the given molar heat capacity of 28.2 J/mol°C and dividing it by the molar mass of sodium, which is 23.0 g/mol. This calculation gives us the specific heat of sodium per gram, which is an important property used in heat exchange units for cooling purposes.

To find the specific heat of sodium, the formula we use is:

Specific heat (c) = Molar heat capacity (C) / Molar mass (M)

By plugging in the numbers:

c = 28.2 J/mol°C / 23.0 g/mol = 1.226 J/g°C

This result allows us to understand the heat absorption capacity of sodium as a metal. Since most metals have specific heats less than 1 J/g°C, sodium's higher specific heat makes it effective for use in certain cooling applications.

Answer 2

The specific heat of sodium is 1,23J/g°C

Step-by-step explanation:

Using the atomic weight of sodium (23g/mol) and the atomic weight definition, we have that each mole of the substance has 23 grams of sodium.

starting from this, we use the atomic weight of sodium to convert the units from J / mol ° C to J / g ° C

`28,2 (J)/(mol C) x (1mol)/(23g) = 1,23 J/g C`