Question

What is the expression and value of "six less than the quotient of a number and two, increased by ten" when n = 8?

StartFraction n Over 2 EndFraction minus 6 + 10; when n = 8, the value is 8.

6 minus StartFraction n Over 2 EndFraction + 10; when n = 8, the value is 12.

StartFraction n Over 2 EndFraction minus 6 + 10; when n = 8, the value is 11.

6 minus StartFraction n Over 2 EndFraction + 10; when n = 8, the value is 9.

Answer 1

the one that ends in 8

Explanation:

Answer 2

Option 1 - StartFraction n Over 2 EndFraction minus 6 + 10; when n = 8, the value is 8.

Explanation:

Given : Expression "six less than the quotient of a number and two, increased by ten".

To find : What is the expression and value of expression when n = 8?

Solution :

Let the number be 'n'.

The quotient of a number and two i.e.
`(n)/(2)`

Six less than the quotient of a number and two i.e.
`(n)/(2)-6`

Six less than the quotient of a number and two, increased by ten i.e.
`(n)/(2)-6+10`

The required expression is
`(n)/(2)-6+10`.

Now, when n=8,

`(n)/(2)-6+10=(8)/(2)-6+10`

`(n)/(2)-6+10=4-6+10`

`(n)/(2)-6+10=8`

The value of the expression is 8.

Therefore, option 1 is correct.

StartFraction n Over 2 EndFraction minus 6 + 10; when n = 8, the value is 8.