Question

given that a test statistic in a left tailed test is z equals -1.25, use a 0.05 significance level to find the p-value and state the conclusion about the null hypothesis

Answer 1

The p-value of the test is 0.106.

The null hypothesis will be accepted at 5% level of significance.

Explanation:

The hypothesis test is left-tailed.

The test statistic value is: z = -1.25.

The significance level of the test is: α = 0.05.

The p-value of a left-tailed hypothesis test is:

`p-value=P(Z<z)=P(Z<-1.25)=0.10565\approx0.106`

The p-value of the test is 0.106.

**Use the z-table for the probability.

Decision rule:

If the p-value is less than the significance level the null hypothesis will be rejected and if it is more than the significance level the null hypothesis will be accepted.

The p-value = 0.106 > α = 0.05.

The null hypothesis will be accepted at 5% level of significance.