In order to factor a polynomial
, you have to find its roots
. Then, you can write
![P(x)=a(x-x_1)(x-x_2)\ldots(x-x_n)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/slnk8aem9dchnf1xqhenpo4ujncrzrhdr3.png)
where
is the leading coefficient of
![P(x)](https://img.qammunity.org/2021/formulas/mathematics/high-school/3zdmxatpd6vn82buq130qfdwvwobmknmtg.png)
a: Let's try to solve
![12u^2+5u+3=0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vnimeoorbh5icsiqmjd24l0t6i9nwhqcar.png)
the disciminant of this quadratic function is
![\Delta = b^2-4ac=25-144=-119](https://img.qammunity.org/2021/formulas/mathematics/middle-school/a9yqey6emk6rg0oy22gbkduqhb9qjxjfv4.png)
So, this quadratic function has no roots, which implies that it cannot be factorised (using real numbers, at least. Are you allowing complex numbers? Let me know in that case)
b: Similarly, we set up
![50g^2 - 15g - 2=0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/79uj0r8zhfsyq31c4qpo6927nwpbgcfbik.png)
This time we can find the two solutions
![g_1 = -(1)/(10),\quad g_2=(2)/(5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/m98jwc3z0yd6kuiqv74fwdsfc5vvy61l3n.png)
which yields the factorization
![50g^2 - 15g - 2=50\left(g+(1)/(10)\right)\left(g-(2)/(5)\right)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/w45wvmpu78wlxow861aqhqhck89yhpxbwy.png)