76.4k views
3 votes
^ = squared
Factorise x^ + 4x - 12

User Yahwe Raj
by
8.2k points

1 Answer

0 votes

The answer for the above problem is found to be "(x+6)X(x-2)"

Explanation:


x^(2) + 4x - 12

= x^2 + 4x + 4 - 4 - 12

=x^2+ 4x + 4 - 16

=(x+2)^2 - 4^2

=(x+2+4)X(x+2-4)

=(x+6)X(x-2)

here is the explanations

since we have x^2, so we try to write the equation in (a+b)^2 = a^2 + 2ab + b^2 form.

to make it in square form we add 4 ( see at the second line). now we took 4 extra so we subtract 4 again.

in third line we have now x^2 + 4x + 4, this is perfect square in the form of (x+4)^2. next we took 16 as 4^2

in fourth line we apply (a+b)X(a-b) = a^2 - b^2 formula. here we took a = (x+4) and b= 4

then finally we get the answer as (x+6)X(x-2)

User Bonfix Ngetich
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories