Question

Solve the following equation for x.

12x^2-36x=0

Answer 1

`\qquad\qquad\huge\underline{{\sf Answer}}♨`

Let's solve for x ~

`\qquad \sf  \dashrightarrow \:12 {x}^(2) - 36x = 0`

`\qquad \sf  \dashrightarrow \:12 x({x}^{} - 3) = 0`

`\qquad \sf  \dashrightarrow \:12x = 0 \: \: or \: \: x - 3 = 0`

`\qquad \sf  \dashrightarrow \:x = 0 \: \: or \: \: x = 3`

Therefore, the possible values of x are 0 and 3