Question

What is the distance from the point (a, -b, -4) to the origin?

O V22-62-16 units
O V22-b2+16 units
O Va+b2+ 16 units
O
Va2 +62 - 16 units

Answer 1

`√(a^2+b^2+16)\text{ units}`

Explanation:

The distance is found using the distance formula:

`d=√((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)`

Then the distance from the given point to the origin is ...

`d=√((a-0)^2+(-b-0)^2+(-4-0)^2)\\\\=\boxed{√(a^2+b^2+16)\ \dots\text{ units}}`