Question

Imagine two doors 1 meter apart on a wall. How fast does an average person (84 kg) have to walk to be able to go through both doors simultaneously? (Hint: diffraction will be observed when the wavelength is comparable to the slit separation) O 8 x 10-36 m s1 O 8 x 1036 ms1 O impossible to calculate O 100 ms1

Answer 1

The velocity of average person is
`8*10^(-36)\ m/s`

(1) is correct option.

Step-by-step explanation:

Given that,

Wavelength = 1 m

Mass of average person = 84 kg

We need to calculate the velocity of average person

Using De Broglie wavelength

`\lambda=(h)/(mv)`

`v=(h)/(m\lmbda)`

Where,
`\lambda` = wavelength

h = plank constant

m = mass

v = velocity

Put the velocity into the formula

`v=(6.626*10^(-34))/(84*1)`

`v=8*10^(-36)\ m/s`

Hence, The velocity of average person is
`8*10^(-36)\ m/s`