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A 10-cm-long thin glass rod uniformly charged to 12.0 nCnC and a 10-cm-long thin plastic rod uniformly charged to - 12.0 nCnC are placed side by side, 4.40 cmcm apart. What are the electric field strengths
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A 10-cm-long thin glass rod uniformly charged to 12.0 nCnC and a 10-cm-long thin plastic rod uniformly charged to - 12.0 nCnC are placed side by side, 4.40 cmcm apart. What are the electric field strengths E1E_1 to E3E_3 at distances 1.0 cm, 2.0 cm, and 3.0 cm from the glass rod along the line connecting the midpoints of the two rods?

User Amatsukawa
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Answer:

Step-by-step explanation:

The electric field at each distances was gotten and then considering the plastic road, the value of the new z was also gotten. that value is used to calculate the electric field E2. The detailed steps is as shown in the attachment.

A 10-cm-long thin glass rod uniformly charged to 12.0 nCnC and a 10-cm-long thin plastic-example-1
User Nyasha
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