First, let's write what the question says in equation form:
(The length of a rectangle is 2 units more than the width)
L = w + 2
(The area is 63 units)
L * w = 63
Since we already know the value of L ('w + 2'), we can simply input that into the equation to solve for area:
L * w = 63
(w + 2) * w = 63
w^2 + 2w = 63
Subtract both sides by 63:
w^2 + 2w - 63 = 0
Factor:
(w + 9)(w - 7) = 0
We get two answers:
{-9, 7}
Since the width can't be negative, the only possible answer is 7.
w = 7
We can input 'w' into the first equation:
L = 7 + 2
L = 9
The width is 7 units, and the length is 9 units,
-T.B.