Question

A certain gas is present in a 15.0 LL cylinder at 2.0 atmatm pressure. If the pressure is increased to 4.0 atmatm the volume of the gas decreases to 7.5 LL . Find the two constants kiki, the initial value of kk, and kfkf, the final value of kk, to verify whether the gas obeys Boyle’s law by entering the numerical values for kiki and kfkf in the space provided.

Answer 1

Step-by-step explanation:

According to Boyle's law, pressure of a gas is inversely proportional to its volume at constant temperature and moles.

Mathematically, P =
`(k)/(V)`

where, k = proportionality constant

Also, formula for initial pressure and volume is as follows.

`P_(i) = (k_(i))/(V_(i))`

or,
`k_(i) = P_(i) * V_(i)`

=
`2 atm * 15 L`

= 30 atm L

Now, we will calculate the value of
`k_(f)` as follows.

`k_(f) = P_(f) * V_(f)`

=
`4 atm * 7.5 L`

= 30 atm L

Hence, as
`k_(i) = k_(f)` this means that it signifies that gas obeys boyle's law.