Question

A supermarket is selling two types of​ candies, orange slices and strawberry leaves. The orange slices cost $1.27 per pound and the strawberry leaves cost $1.77 per pound. How many pounds of each should be mixed to get a 88​-pound mixture that sells for $11.16​?

Answer 1

8 pound of orange slices

5 pound of strawberry leaves.

Explanation:

Let X = weight of orange slices and Y = weight of strawberry leaves.

Therefore,

Quantities:

i. X + Y = 13

Cost:

ii. 1.27X + 1.77Y = 19.01

Rearranging i. equation:

Y = 13 – X

Substituting this in the second equation

1.27X + 1.77*(13 – X) = 19.01

1.27X + 23.01 - 1.77X= 19.01

0.5X = 4

X = 8

Inputting the value X into i. equation:

8 = 13 – Y

Y = 5.

Answer 2

The question here has wrong numbers. Here is the correct question:

A supermarket is selling 2 types of candies, orange slices and strawberry leaves. The orange slices cost $1.27 per pound and the strawberry leaves cost $1.77 per pound. How many pounds of each should be mixed to get a 13-pound mixture that sells for $19.01?

Answer:

8 pounds of orange slices and 5 pounds of strawberry leaves

Explanation:

This question is related to simple algebra

Let x represent orange slices weight

Let y represent strawberry leaves weight

The sum of the weights of x and y will be 13 pounds

So first equation will be x + y = 13

The total cost will be $19.01

So the second equation will be

1.27x + 1.77y = 19.01

Using first equation

x + y = 13

x = 13 – y

Substituting this in the second equation

1.27 (13 - y) + 1.77y = 19.01

16.51 – 1.27y + 1.77y = 19.01

16.51 + 0.5y = 19.01

y = 5

Using this value of y to find x

x = 13 – y

x = 13 – 5

x = 8

So 8 pounds of orange slices and 5 pounds of strawberry leaves