For this case we have that by definition, the volume of a cylinder is given by:
![V = \pi * r ^ 2 * h](https://img.qammunity.org/2021/formulas/mathematics/middle-school/16apv4ym1yc773qcgsky2yo2c2rygbd01y.png)
Where:
r: It is the radius of the cylinder
h: It is the height of the cylinder
According to the data of the statement we have to:
![r = \frac {11} {2} = 5.5 \ in](https://img.qammunity.org/2021/formulas/mathematics/middle-school/21k8qdhhql9uwht00n3c4jahta40v21d72.png)
Taking
![\pi = 3.14](https://img.qammunity.org/2021/formulas/mathematics/middle-school/y04rzsjmfedht1b41g0s1en1rzhn5jx8g3.png)
Substituting:
![V = 3.14 * {5.5) ^ 2 * h\\\\V = 94,985h](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8ccca0t179042bbm4c7k47w2s5cxif6s07.png)
This is approximately:
![V = 95h](https://img.qammunity.org/2021/formulas/mathematics/middle-school/m8km5r9rpjyacotu8gohetslje1vnlvln1.png)
Answer:
![V = 95h \ in ^ 3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/seddlkhv5j5bag0x04k6fjp82kb8cjxm81.png)