Question

According to a simplified model of a mammalian heart, at each pulse approximately 20 g of blood is accelerated from 0.25 m/s to 0.35 m/s during a period of 0.10 s. What is the magnitude of the force exerted by the heat muscle?

Answer 1

0.02 N.

Step-by-step explanation:

Given:

m = 20 g

= 0.02 kg.

vi = 0.35 m/s

vo = 0.25 m/s

t = 0.1 s

Force, F = m * a

Where,

m = mass of the blood

a = acceleration.

Acceleration, a = (vi - vo)/t

Where,

vi = final velocity

vo = initial velocity

t = time.

a = (0.35 - 0.25)/0.1

= 0.1/0.1

= 1 m/s².

F = 0.02 * 1

= 0.02 N.

Answer 2

0.02 N

Step-by-step explanation:

Force: This can be defined as the product of mass and acceleration. The S.I unit of force is Newton.

The formula of force is given as,

F = ma ............................ Equation 1

Where F = force exerted by the heart muscle, m = mass of the blood, a = acceleration.

Also,

a = (v-u)/t ....................... Equation 2

Where v = final velocity, u = initial velocity, t = time.

Given: v = 0.35 m/s, u = 0.25 m/s, t = 0.1 s

Substitute into equation 2

a = (0.35-0.25)/0.1

a = 0.1/0.1

a = 1 m/s².

Also given: m = 20 g = 0.02 kg.

Substitute into equation 1

F = 0.02(1)

F = 0.02 N.

Hence the force = 0.02 N