Area of the figure = 30.28 m²
Solution:
The given image is splitted into two shapes.
One is rectangle and the other is semi-circle.
Length of the rectangle = 6 m
Width of the rectangle = 4 m
Area of the rectangle = length × width
= 6 m × 4 m
= 24 m²
Area of the rectangle = 24 m²
Diameter of the semi-circle = 4 m
Radius of the semi-circle = 4 m ÷ 2 = 2 m
Area of the semi-circle =
![(1)/(2) \ \pi r^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jrmggb7ndzouopfwgcx2micwya9sesqjo4.png)
![$=(1)/(2) * 3 .14 * 2^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/trrgcz9ad783qmff0d3b92sfgmaocxqlcv.png)
![=6.28](https://img.qammunity.org/2021/formulas/mathematics/middle-school/86c7r58lu7b346om00dclew8k8bj4dj22p.png)
Area of the semi-circle = 6.28 m²
Area of the figure = Area of the rectangle + Area of the semi-circle
= 24 m² + 6.28 m²
= 30.28 m²
Area of the figure = 30.28 m²