Question

For the simple harmonic motion equation d = 5sin(2pi * t) , what is the period? If necessary, use the slash to represent a fraction.

Answer 1

The period is 1

Explanation:

Answer 2

Period is 1

Solution:

Given that,

For the simple harmonic motion equation:

`d = 5\ sin(2 \pi t)`

To find: Period

Use the following form to find the period

`y = a\ sin(bx-c) + d`

Where,

a is the amplitude

c is phase shift

d is vertical shift

The period is given as:

`Period = (2 \pi)/(b)`

On comparing,

`y = a\ sin(bx-c) + d\\\\d = 5\ sin(2 \pi t)`

Thus on comparing we get,

`b = 2 \pi`

Thus,

`Period = (2 \pi)/(b)\\\\Period = (2 \pi )/(2 \pi)\\\\Period = 1`

Thus period is 1