Question

∆ABC m∠B = 90° AB = 4 BC = 3
Find AC

Answer 1

Explanation:

In ∆ABC, m∠B = 90°

Therefore ∆ABC is a right angled triangle with sides AB = 4 & BC = 3. AC is the hypotenuse.

Hence, by Pythagoras theorem:

`AC^2 = AB^2 +BC^2 \\ \\ \therefore \: AC = √(AB^2 +BC^2 ) \\ = \sqrt{ {4}^(2) + {3}^(2) } \\ = √(16 + 9) \\ = √(25) \\ = 5 \\ \\ \huge \red{ \boxed{ \therefore \: AC = 5 \: units}}`