Answer:
c. 13.6%
Explanation:
Mean weight (μ)= 22.0 ounces
Standard deviation (σ) = 1.0 ounce
Assuming a normal distribution, for any given weight X, the corresponding z-score is found by the following equation:
For X = 23.1 ounces:
According to a z table, a score of 1.1 corresponds to the 86.43th percentile of a normal distribution. Therefore, the percentage of regulation basketballs that weight more than 23.1 ounces is:
The percentage is 13.6%.