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Prove that sin (90-theta) cos (90-theta)= tanA /tanA+1

User Stzoannos
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5 votes

Answer:

Please see attached picture for full solution.

I changed the rhs to tanθ/tanθ+1 since the angle cannot be A and θ.

tanθ= sinθ/cosθ

cosθ/sinθ= cotθ= 1/tanθ

From 4th last line, here is the step I skipped:

1 ÷ [1 +(1/tanθ)] = 1 ÷ [(tanθ/tanθ)+(1/tanθ)]

Prove that sin (90-theta) cos (90-theta)= tanA /tanA+1-example-1
User Kerri Brown
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