Answer:
Common ratio is 8.
First term is 4
Recursive:
![a_n=8a_(n-1)</p><p> \: a_1 = 4</p><p>](https://img.qammunity.org/2021/formulas/mathematics/high-school/k87wfg3krioocdc4gktlhntmwbglaecdlb.png)
Explanation:
The given sequence is:
{4,32,256,2048,16,384,…}
The common ratio of this sequence is obtained by dividing a term in the sequence by a previous term.
This is given by:
![r = (32)/(4) = 8](https://img.qammunity.org/2021/formulas/mathematics/high-school/27sj3p3t6t2qar7mal5uek0ykvff28exoq.png)
The term of the sequence is the term that begins the sequence.
This is 4.
The recursive definition is given by:
![a_n=ra_(n-1)</p><p>](https://img.qammunity.org/2021/formulas/mathematics/high-school/uz6hr2pfgx0v1065eglrm4v7x8hzod9jjs.png)
This implies that:
![a_n=8a_(n-1)</p><p> \: a_1 = 4</p><p>](https://img.qammunity.org/2021/formulas/mathematics/high-school/k87wfg3krioocdc4gktlhntmwbglaecdlb.png)