Question

Suppose Rick has 40 ft of fencing with which he can build a rectangular garden.Letxrepresent the length of the garden and letyrepresent the width.(a) Write and inequality representing the fact that the total perimeter of thegarden is at most 40 ft.(b) Sketch part of the solution set for this inequality that represents all possiblevalues for the length and with of the garden. (Hint:Note that both the lengthand the width must be positive.)

Answer 1

Explanation:

Answer:

Explanation:

Since Rick has 40ft of fencing

Then, the perimeter cannot be more than 40ft if he decided to lay the block on a single layer and not on each other

Then if the length is x

And the breadth is y

Perimeter of a rectangle is 2(l+b)

Therefore,

Perimeter is less than or equal to 40ft

2(l+b) ≤ 40

b. 2(l+b)≤ 40

Then divide both side by 2

l+b≤ 20.

Then l ≤ 20-b

Also, b ≤ 20-l

Check attachment for graph

Answer 2

20 >= x + y

Explanation:

Given:

- The length of garden = x

- The width of the garden = y

- Total fence available = 40 ft

- Rectangular garden

Find:

(a) Write and inequality representing the fact that the total perimeter of thegarden is at most 40 ft.

(b) Sketch part of the solution set for this inequality that represents all possiblevalues for the length and with of the garden.

Solution:

- The perimeter of the rectangular garden is P at most 40 ft:

P >= 2*x + 2*y

40 >= 2*x + 2*y

20 >= x + y

- The sketch of the graph will be all points in the shaded region denoted by the inequality as follows:

y =< 20 - x

- See the triangular shaded region.