Question

A cube of mass m 1 = 7.0 kg is sitting on top of a second cube of the same size and mass m 2 = 0.7 kg while both are in free fall. Ignoring any air resistance, what is the magnitude of the normal force with which the bottom cube is acting on the top cube?

Answer 1

0 N

Explanation:

We are given that

`m_1=7 kg`

`m_2=0.7 kg`

Total mass =
`m_1+m_2=7+0.7=7.7 Kg`

We have to find the magnitude of the normal force with which the bottom cube is acting on the top cube.

When both cube are fall freely then

g=
`0m/s^2`

Then, the weight=
`mg=7.7* 0=0 N`

The direction of weight is downward.

We know that

Normal force is equal to weight and act in opposite direction of weight.

When the weight is zero N then

The magnitude of the normal force with which the bottom cube is acting on the top cube=0 N