Question

Suppose that at room temperature, a certain aluminum bar is 1.0000 m long. The bar gets longer when its temperature is raised. The length l of the bar obeys the following relation: l=1.0000+2.4×10−5T, where T is the number of degrees Celsius above room temperature. What is the change of the bar's length if the temperature is raised to 16.1 ∘C above room temperature?

Answer 1

The change of the bar's length is
`3.9*10^(-4) m`

Step-by-step explanation:

The bar length is a function of temperature T above room temperature:

`L(T)=1.0000+2.4*10^(-5) T`

So, if we evaluate at T= 16.1 C above room temperature

`L(16.1)=1.0000+2.4*10^(-5) (16.1)`

`L=1.00039 m`

Now we can find the change of the bar length with the difference of L and Lo (the length at room temperature)

`L- L_0=1.00039-1.0000 = 3.9*10^(-4) m`