Question

A baseball was hit and reached its maximum height in 3.00s. Find (a) its initial velocity; (b) the height it reaches.[29.4 m/s; 44.1m]

Answer 1

u= 29.43 m/s

h=44.14 m

Step-by-step explanation:

Given that

t= 3 s

We know that acceleration due to gravity ,g = 9.81 m/s² (Downward)

Initial velocity = u

Final velocity ,v= 0 (At maximum height)

We know v = u +a t

v=final velocity

u=initial velocity

a=Acceleration

Now by putting the values in the above equation

0 = u - 9.81 x 3

u= 29.43 m/s

The maximum height h is given as

v² = u ² - 2 g h

0² = 29.43 ² - 2 x 9.81 x h

`h=(29.43^2)/(2* 9.81)\ m`

h=44.14 m