Question

If 3.78 L of nitrogen gas and 28.73 L of hydrogen gas were allowed to react, how many litres of ammonia gas could form?

Answer 1

Volume of ammonia formed is 7.56 L

Step-by-step explanation:

Volume of 1 mol of gas is 24 L.

No. of mol in 3.78 L of nitrogen =
`(3.78)/(24)=0.1575\ mol`

No. of mol in 3.78 L of hydrogen =
`(28.73 )/(24)=1.197\ mol`

`N_2 +3H_2 \rightarrow 2NH_3`

I mol of nitrogen required 3 moles of hhydrogen.

So, 0.1575 mol of nitrogen will require 0.4725 moles of hydrogen.

As moles of hydrogen is 1.197, therefore, nitrogen will be the limiting reagent.

So,

1 mol of nitrogen forms 2 moles of ammonia

0.1575 mol of nitrogen will form 0.1575 mol × 2 = 0.315 mol of ammonia

Volume of ammonia = 0.315 × 24

= 7.56 L

Volume of ammonia formed is 7.56 L