Answer:
30183.92 N
Step-by-step explanation:
Force: This can be defined as the product of the mass of a body and it's acceleration. The S.I unit of force is Newton (N).
From the question,
The kinetic energy of the bullet = Work done by friction in the tree in stopping the bullet.
1/2mv² = Fₓd ................... Equation 1
Where m = mass of the bullet, v = velocity of the bullet, Fₓ = average Frictional force exerted by the tree on the bullet, d = depth of penetration.
Make Fₓ the subject of the equation,
Fx = mv²/2d .................... Equation 2
Given: m = 4.65 g = 0.00465 kg, v = 824 m/s, d = 5.23 cm = 0.0523 m.
Substitute into equation 2
Fₓ = 0.00465(824)²/(2×0.0523)
Fₓ = 30183.92 N.
Hence the average frictional force = 30183.92 N