Question

Suppose George loses 66​% of all staring contests. ​(a) What is the probability that George loses two staring contests in a​ row? (b) What is the probability that George loses four staring contests in a​ row? Assume that each game played is independent of the rest.

Answer 1

a) 43.56% probability that George loses two staring contests in a​ row.

b) 18.97% probability that George loses four staring contests in a​ row.

Explanation:

In each staring contest, George has a 66% probability of losing.

(a) What is the probability that George loses two staring contests in a​ row?

`P = (0.66)^(2) = 0.4356`

43.56% probability that George loses two staring contests in a​ row.

(b) What is the probability that George loses four staring contests in a​ row? Assume that each game played is independent of the rest.

`P = (0.66)^(4) = 0.1897`

18.97% probability that George loses four staring contests in a​ row.