Explanation:
The only way the answer could be E is if the x² term under the radical is supposed to be t².
f(x) = ∫₄²ˣ √(t² − t) dt
f'(x) = √((2x)² − 2x) (2)
f'(x) = 2√(4x² − 2x)
f'(2) = 2√(4(2)² − 2(2))
f'(2) = 2√12
3.6m questions
4.6m answers