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Solve for a side in right triangles

Solve for a side in right triangles-example-1

1 Answer

7 votes

Answer:

AC ≈ 2.18

Explanation:

Using the tangent ratio in the right triangle

tan70° =
(opposite)/(adjacent) =
(BC)/(AC) =
(6)/(AC)

Multiply both sides by AC

AC × tan70° = 6 ( divide both sides by tan70° )

AC =
(6)/(tan70) ≈ 2.18 ( to the nearest hundredth )

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