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Terrence and Lee were selling magazines for a charity. In the first week, Terrance sold 30% more than Lee. In the second week, Terrance sold 12 magazines, but Lee did not sell any. If Terrance sold 50% more than Lee by the end of the second week, how many magazines did Lee sell? Choose any model to solve the problem. Show your work to justify your answer.

1 Answer

3 votes

Answer:

Lee sold 60 magazines

Explanation:

1st week:

Lee sold = x magazines

Terrence sold
=x+0.3x=1.3x magazines (30% more)

2nd week:

Lee sold = 0 magazines

Terrence sold = 12 magazines

Total:

Lee sold = x + 0 = x magazines

Terrence sold = 1.3x + 12 magazines

If Terrance sold 50% more than Lee by the end of the second week, then

x - 100%

1.3x + 12 - 150% (50% more), then


(x)/(1.3x+12)=(100)/(150)\\ \\150x=100(1.3x+12)\\ \\150x=130x+1,200\\ \\150x-130x=1,200\\ \\20x=1,200\\ \\x=60

Hence, Lee sold 60 magazines

User Huseyin Yagli
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