Question

If a tensile load of 100 pounds is applied to a rod which has a diameter of 1 inch, what is the stress in the rod?

Answer 1

`\sigma=127.32\ pounds/in^2`

Step-by-step explanation:

Given that

Load ,P = 100 Pounds

Diameter ,d= 1 inch

We know that stress in the rod due to load P is given as

`\sigma=(P)/(A)`

P=Load

A=Area

Now by putting the values in the above equation, we get

`\sigma=(100)/((\pi)/(4)* 1^2)\ Pounds/in^2`

`\sigma=127.32\ pounds/in^2`