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A source emits sound with a frequency of 860 Hz. It is moving at 20.0 m/s toward a stationary reflecting wall. If the speed of sound is 343 m/s, what frequency does an observer riding with the source hear

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Answer:

Step-by-step explanation:

f = 860 Hz

velocity of source, vs = 20 m/s

velocity of sound, v = 343 m/s

use the formula of doppler's effect

the frequency reflected from the wall is


f' = (v)/(v+ v_(s))* f


f' = (343)/(343+20)* 860

f' = 812.62 Hz

Frequency heard by the observer


f'' = (343)/(343-20)* 812.62

f'' = 862.93 Hz

User Divakar Gujjala
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