Answer:
(a) The Venn diagram is attached below.
(b) The probability that neither university admits Ramon is 0.20.
(c) The probability that Ramon gets into Stanford but not Harvard 0.30.
Explanation:
Let's denote the events as follows:
H = Ramon gets admitted to Harvard
S = Ramon gets admitted to Stanford.
The information provided is:
P (H) = 0.50
P (S) = 0.50
P (H ∩ S) = 0.20
(a)
The Venn diagram is attached below.
(b)
Compute the probability that Ramon gets admitted in neither Harvard nor Stanford as follows:
![P(H^(c)\cup S^(c))=1-P(H\cup S) \\= 1 - [P(H)+P(S)-P(H\cap S)]\\=1-[0.50+0.50-0.20]\\=1-0.80\\=0.20](https://img.qammunity.org/2021/formulas/mathematics/college/x26rsuoj845ggdlbfhim1efc0chz39ufhm.png)
Thus, the probability that neither university admits Ramon is 0.20.
(c)
Compute the probability that Ramon gets admitted in Stanford but not in Harvard as follows:
![P(H^(c)\cup S)=P(S)-P(H\cap S) \\= 0.50-0.20\\=0.30](https://img.qammunity.org/2021/formulas/mathematics/college/fwx1jhzdy2790zauvsaqy06ty1x9pul1dl.png)
Thus, the probability that Ramon gets into Stanford but not Harvard 0.30.