Question

Bus A travels according to the function y = 125/5x where y is distance traveled in miles and x is time in hours. Bus B travels according to the graph below, where the distance y is a function of time x. Which bus travels faster? Include all necessary calculations in your final answer.

Answer 1

some of the equations are not couply able so here u go

The graph of the question in the attached figure

we know that

the linear equation in slope intercept form is equal to

y = mx + b

where

m is the slope

b is the y-intercept

x --> is the time in hours

y --> is the distance in miles

In this problem we have

Bus A

y = 125/5 x

The slope of the linear equation represent the speed of the bus

so

The speed of bus A is

125/5 = 25 miles/hour

Bus B

Find the slope

take two points from the graph

(0,0) and (3,200)

The formula to calculate the slope between two points is equal to

m = y2 + y1/x2 - x1

substitute

m = 200 - 0/3 - 0

m = 66.67 miles/hour

Compare the slope Bus A with the slope Bus B

66.67 mile/hour > 25 miles /hour

therefore

Bus B travel faster

Answer 2

Bus B travel faster

Explanation:

The graph of the question in the attached figure

we know that

the linear equation in slope intercept form is equal to

`y=mx+b`

where

m is the slope

b is the y-intercept

x ---> is the time in hours

y ---> is the distance in miles

In this problem we have

Bus A

`y=(125)/(5)x`

The slope of the linear equation represent the speed of the bus

so

The speed of bus A is

`(125)/(5)=25\ miles/hour`

Bus B

Find the slope

take two points from the graph

(0,0) and (3,200)

The formula to calculate the slope between two points is equal to

`m=(y2-y1)/(x2-x1)`

substitute

`m=(200-0)/(3-0)`

`m=66.67\ (miles)/(hour)`

Compare the slope Bus A with the slope Bus B

`66.67\ (miles)/(hour) > 25\ (miles)/(hour)`

therefore

Bus B travel faster