Question

How many moles of NaCl will be produced from 83.0g of Na, assuming Cl2 is available in excess?

Answer 1

2.57

Step-by-step explanation:

Answer 2

Answer: The number of moles of
`NaCl` produced will be, 3.61 moles.

Explanation : Given,

Mass of
`Na` = 83.0 g

Molar mass of
`Na` = 23 g/mol

First we have to calculate the moles of
`Na`

`\text{Moles of }Na=\frac{\text{Given mass }Na}{\text{Molar mass }Na}`

`\text{Moles of }Na=(83.0g)/(23g/mol)=3.61mol`

Now we have to calculate the moles of
`NaCl`

The balanced chemical equation is:

`2Na+Cl_2\rightarrow 2NaCl`

From the reaction, we conclude that

As, 2 mole of
`Na` react to give 2 mole of
`NaCl`

So, 3.61 mole of
`Na` react to give 3.61 mole of
`NaCl`

Therefore, the number of moles of
`NaCl` produced will be, 3.61 moles.