Answer:
38.9 square inches.
Explanation:
We are asked to find the difference in area covered by a single 3 inch windshield wiper operating with a central angle of 138 degrees compared to a pair of 5 inch wipers operating together each having a central angle of 114 degrees.
We will use area of sector formula to solve our given problem as:
, where, r represents radius and theta represents central angle.
Let us find area of sector with central angle 140 degree and radius 3 inch.
![\text{Area of sector}=(138)/(360)* \pi (3)^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/rumka1hm24r8fekrq9czzz82jlx2fgpw21.png)
![\text{Area of sector}=(138)/(360)* 9\pi](https://img.qammunity.org/2021/formulas/mathematics/high-school/ec4z1mezo3csh1rjg4nu3e06vxzb71g4i1.png)
![\text{Area of sector}=10.83849](https://img.qammunity.org/2021/formulas/mathematics/high-school/soxgiz53uvcppwq342ifrgncobyejhhz37.png)
Now, we will find area of sector with central angle 114 degree and radius 5 inch and multiply by 2 as:
![\text{Area of sector}=2((114)/(360)* \pi (5)^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/yecvdqxs5hut8xm5nel5s23t6bwdcafz36.png)
![\text{Area of sector}=2((114)/(360)* 25\pi)](https://img.qammunity.org/2021/formulas/mathematics/high-school/iotn4mhrpid9f3stz1x1z5lvejnj03fnbl.png)
![\text{Area of sector}=(114)/(360)* 50\pi](https://img.qammunity.org/2021/formulas/mathematics/high-school/ti5dxquxc6obkmp8n6qhvzwjgxxvl9n1r5.png)
![\text{Area of sector}=49.74188](https://img.qammunity.org/2021/formulas/mathematics/high-school/a1oj2qodcss2awnkz3edjmc9m99i2jza6h.png)
Let us find difference of area as shown below:
![\text{Difference of areas}=49.74188-10.83849](https://img.qammunity.org/2021/formulas/mathematics/high-school/r279f9csnluljer2alhpfreifgoyzyqnz1.png)
![\text{Difference of areas}=38.90339](https://img.qammunity.org/2021/formulas/mathematics/high-school/ah9lf8j64xztiig34h0h0hgdfb46fcsyk0.png)
![\text{Difference of areas}\approx 38.9](https://img.qammunity.org/2021/formulas/mathematics/high-school/7xa85ygro74jj1w01u3euupsuw1dkabzx0.png)
Therefore, the difference in area covered is approximately 38.9 square inches.