Question

Tom has two pendulums with him. Pendulum 1 has a ball of mass 0.2 kg attached to it and has a length of 5 m. Pendulum 2 has a ball of mass 0.6 kg attached to a string of length 1 m. How does mass of the ball affect the frequency of the pendulum? The mass of the ball of the pendulum is inversely proportional to the period; hence it will affect the frequency of the pendulum. The mass of the ball of the pendulum will not affect the period; hence it will not affect the frequency of the pendulum. The mass of the ball of the pendulum is directly proportional to the period; hence it will affect the frequency of the pendulum. The mass of the ball of the pendulum is directly proportional to the square of the period; hence it will affect the frequency of the pendulum. Which pendulum will have a higher frequency and why?

Answer 1

A.

The mass of the ball of the pendulum will not affect the period; hence it will not affect the frequency of the pendulum.

B.

Pendulum 2.

Step-by-step explanation:

A.

The mass of the bob of a pendulum is not relevant to its period of oscillation. Its length of the of the pendulum is.

B.

T = 2pi*sqrt(L/g)

For pendulum 1,

L = 5 m

g = 9.8 m/s^2

T1 = 4.49 s.

F1 = 1/T1

= 0.22 hz.

For pendulum 2,

L = 1 m

g = 9.8 m/s^2

T2 = 2 s

F2 = 1/T2

= 0.5 hz.

Pendulum 2.

The shorter the string, the shorter the period. So the shorter one will have a higher frequency.