Answer:
(1,-8)
Explanation:
We were given three vertices of a parallelogram to be:
(3,-2), (-1,-4), (5,-6).
After plotting the points as shown in the attachment, we realize (3,-2) and (-1,-4) form a diagonal.
The midpoint of this diagonal using the midpoint formula is
![((x_1+x_2)/(2),(y_1+y_2)/(2))](https://img.qammunity.org/2021/formulas/mathematics/high-school/8ale4wsv3emnmytc9vjfn7lms5i6v3dog5.png)
is
![((-1+5)/(2),(-4+-6)/(2))=(2,-5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ey3y9ddicrkpynsly0j9bv8q1maui8xb20.png)
Recall that, the midpoint of both diagonals are the same.
Let the fourth point have coordinates (x,y).
Then using the midpoint formula again with (3,-2), we have:
![((3+x)/(2),(y+-2)/(2))=(2,-5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/z6mi4pcu8eb7y7bh3f3bjgr93d48za87fk.png)
This implies that:
and
![y-2=-10](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1b0tvh9jmyqci3hf6kwtx59uicbw6ahooe.png)
and
![y=-10+2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wjpdhh3zo9c9lmhn0wwrwc3tc34s65zkve.png)
x=1 and y=-8
The coordinates of the fourth point are:
(1,-8)