Answer : The volume of
required is, 0.304 L
Explanation :
First we have to calculate the moles of uranium.

Molar mass of uranium = 238.03 g/mol

Now we have to calculate the moles of

The given balanced chemical reaction is:

From the balanced chemical reaction we conclude that,
As, 1 mole of uranium react with 3 moles of

So, 0.00420 mole of uranium react with
moles of

Now we have to calculate the volume of

Using ideal gas equation:

where,
P = Pressure of
gas = 745 mmHg = 0.980 atm (1 atm = 760 mmHg)
V = Volume of
gas = ?
n = number of moles
= 0.0126 mole
R = Gas constant =

T = Temperature of
gas =

Putting values in above equation, we get:


Thus, the volume of
required is, 0.304 L