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Recall that the perimeter of a rectangle is P=2(W+L), where W is the width and L is the length.

The length of a rectangle is 26 feet more than the width. If the perimeter is 60 feet, then what is the length of the rectangle,

User Anna Lam
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Final answer:

To find the length of the rectangle, use the given information about the width and perimeter. Solve the equations to find the values of the variables and determine the length of the rectangle.

Step-by-step explanation:

To find the length of the rectangle, we can use the information given in the problem. Let's let the width be represented by W and the length be represented by L. We are told that the length is 26 feet more than the width, so we can write the equation L = W + 26. We are also given that the perimeter of the rectangle is 60 feet, so we can write the equation 60 = 2(W + L). We can substitute the value of L from the first equation into the second equation to solve for W. After finding the value of W, we can substitute it back into the first equation to find the value of L.



Let's start with the first equation: L = W + 26. Since we have an equation with two variables, we'll need to use the second equation to solve for the variables. Let's substitute the value of L in the second equation: 60 = 2(W + (W + 26)). We can simplify this equation by combining like terms: 60 = 2(2W + 26). We can distribute the 2 to the terms inside the parentheses: 60 = 4W + 52. We can then subtract 52 from both sides of the equation: 8 = 4W. Finally, we can divide both sides of the equation by 4 to solve for W: W = 2.



Now that we have the value of W, we can substitute it back into the first equation L = W + 26. This gives us: L = 2 + 26. We can simplify this equation to find that L = 28.

User SOF User
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