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How do I solve the following equation? A certain car model has a mean gas mileage of 34 miles per gallon (mpg) with a standard deviation 3 mpg. a pizza delivery company buys 59 of these cars. what is the probability that the average mileage of the fleet is greater than 33.8 mpg?

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Answer:

The probability that the average mileage of the fleet is greater than 33.8 mpg is 0.695

Explanation:

The car model has a mean gas mileage of 34 miles per gallon (mpg) with a standard deviation 3 mpg. We want to find the probability that the average mileage of the fleet is greater than 33.8 mpg, if a pizza delivery company buys 59 of these cars.

We calculate the z-score using:


z=(x-\mu)/((\sigma)/(√(n) ) )

We substitute
\mu=34,\sigma=3,n=59,x=33.8


z=(33.8-34)/((3)/(√(59) ) )


z=-0.52

From the standard normal distribution table, P(X>33.8)=0.695

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