Answer: 27.61g
Step-by-step explanation:
First thing first, generate a balanced equation for the reaction as illustrated below:
CrCl3 + 3AgNO3 —> Cr(NO3)3 + 3AgCl
Next, we'll find the molar mass of CrCl3 and AgCl:
Molar Mass of CrCl3 = 52 + (3x35.5)
= 158.5g/mol
Molar Mass of AgCl = 108 + 35.5 = 143.5g/mol
But from the balanced equation, 3 mol of AgCl was produced. Therefore, the mass conc. of AgCl from the equation = 3 x 143.5 = 430.5g.
From the equation,
158.5g of CrCl3 produced 430.5g of AgCl.
Therefore, Xg of CrCl3 will produce 75g of AgCl i.e
Xg of CrCl3 = (158.5x75) / 430.5 =27.61g.
So, 27.61g of CrCl3 will produce 75g of AgCl