Question

What are the coordinates of vertex J of the pre-image? (0, -4) (0, -1) (0, 0) (0, 4)

Answer 1

Answer: (0,-4)

Explanation:

Answer 2

(0,-4)

Explanation:

The complete question is

Quadrilateral JKLM was dilated according to the rule

DO,1/2 (x,y)( 1/2x1/2y) to create the image quadrilateral J'K'L'M', which is shown on the graph.

What are the coordinates of vertex J of the pre-image?

The picture in the attached figure

we know that

The rule of the dilation is

(x,y) -----> (1/2x,1/2y)

The coordinates of vertex J' are (0,-2) ----> see the graph

therefore

The x-coordinate of J (pre-image) multiplied by 1/2 must be equal to the x-coordinate of J' (image)

`(1)/(2)x=0` ----->
`x=0`

The y-coordinate of J (pre-image) multiplied by 1/2 must be equal to the y-coordinate of J' (image)

`(1)/(2)y=-2` ----->
`y=-4`

therefore

The coordinates of J are (0,-4)