Question

A woman earns $1,350 in interest from two accounts in 1 year. If she has three times as much invested at 7% as she does at 6%, how much does she have in each account?

Answer 1

$5,000 in the 6% account and $15,000 in the 7% account.

Explanation:

From the question, We are given that the woman earns $1,350 in interest from two accounts, A and B respectively in one year. So, in account A= 6 percent and Account B= 7 percent.

So, If she has three times as much invested at 7 Percent. Then, we will have (7 percent × 3x) = 21 percent(x)

And if she invested 6 percent in the other account (6 Percent × 1x)= 6 Percent (x).

Then, (21/100) x + (6/100) x.

==> 0.21 x + 0.06 x= 0.27 x.

0.27 x will be equals to the interest the woman earns. That is, 0.27 x = $1,350.

Hence, x = $1,350/ 0.27 = $5,000.

In the account A, the woman will have $5,000 and in the account B, the woman will have, 3× $5,000 = $15, 000.

Answer 2

The solution is in the attachment