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Two siblings are in a funny mood and push each other away with a force of 20 N. If sibling 1 has a mass of 50 kg and sibling 2 a mass of 60 kg, what will be the ratio between their respective accelerations (sibling 1 : sibling 2)? (2 significant figures)

User Semimono
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1 Answer

1 vote

Answer:


\large\boxed{\large\boxed{(a_1)/(a_2)=1.2}}

Step-by-step explanation:

Newton's second law states the the net force exerted over a body,
F, is proportional to the product of its mass,
m , and its acceleration,
a :


F=m* a

As a consequence of Newton's third law, action and reaction forces are equal in magnitude and opposite in direction. Hence, 20 N is the same magnitude of the forces over each sibling.

1. Sibling 1:


20N=50kg* a_1

2. Sibling 2:


20N=60kg* a_2

3. Ratio sibling 1: sibling 2:


(20N)/(20N) =(50kg* a_1)/(60kg* a_2)


(a_1)/(a_2)=(60)/(50)=1.2

User Rebra
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